<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
	>

<channel>
	<title>信易科技用户论坛| firsthlc | 动态</title>
	<link>https://forum.shinnytech.com/%e6%88%90%e5%91%98/84800766-20a1-49b6-88d1-ac69e48dcaa1/activity/</link>
	<atom:link href="https://forum.shinnytech.com/%e6%88%90%e5%91%98/84800766-20a1-49b6-88d1-ac69e48dcaa1/activity/feed/" rel="self" type="application/rss+xml" />
	<description>firsthlc的动态信息。</description>
	<lastBuildDate>Tue, 05 May 2026 09:27:19 +0800</lastBuildDate>
	<generator>https://buddypress.org/?v=10.4.0</generator>
	<language>zh-CN</language>
	<ttl>30</ttl>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>2</sy:updateFrequency>
	
						<item>
				<guid isPermaLink="false">5c02c739a74c0edde34966db906c5cb8</guid>
				<title>firsthlc 提了一个新问题 问题</title>
				<link>https://forum.shinnytech.com/?p=24754</link>
				<pubDate>Thu, 11 Jan 2024 06:02:55 +0800</pubDate>

									<content:encoded><![CDATA[<p>这个.tqsdk文件夹是干什么的，能不能删掉</p>
<p> <img loading="lazy" src="https://forum.shinnytech.com/wp-content/uploads/anspress-uploads/d6d06194e79061410d34ca0295cbffdb96b06145_5206.png" /></p>
]]></content:encoded>
				
				
							</item>
					<item>
				<guid isPermaLink="false">afa81ac341753016feec8db1c0b55a11</guid>
				<title>firsthlc 提了一个新问题 问题</title>
				<link>https://forum.shinnytech.com/?p=24727</link>
				<pubDate>Sun, 24 Dec 2023 03:33:45 +0800</pubDate>

									<content:encoded><![CDATA[<p>移仓换月用什么代码实现</p>
]]></content:encoded>
				
				
							</item>
					<item>
				<guid isPermaLink="false">74236b90033de3107857606167aeed03</guid>
				<title>firsthlc 提了一个新问题 问题</title>
				<link>https://www.shinnytech.com/?p=24152</link>
				<pubDate>Mon, 08 May 2023 08:11:20 +0800</pubDate>

									<content:encoded><![CDATA[<p>问题：</p>
<p>每次K线数据更新产生一个新的数据，需要对这些数据进行运算来判断未来趋势，怎么才能实现</p>
<p>比如：</p>
<p>A = max(abs(klines1.iloc[-1].high-klines1.iloc[-2].high),abs(klines1.iloc[-1].low-klines1.iloc[-2].low))</p>
<p>求 sum（A[-20:-1]）的值</p>
<p>能不能实现或者有没有什么办法实现</p>
]]></content:encoded>
				
				
							</item>
		
	</channel>
</rss>