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	<title>信易科技用户论坛| nabatieqiao | 动态</title>
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	<description>nabatieqiao的动态信息。</description>
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				<title>nabatieqiao 提了一个新问题 问题</title>
				<link>https://forum.shinnytech.com/?p=24280</link>
				<pubDate>Sat, 17 Jun 2023 08:27:58 +0800</pubDate>

									<content:encoded><![CDATA[<p>使用MA309五分钟数据，时间2023年6月17日。</p>
<p>快期的SAR</p>
<p> <img loading="lazy" src="https://forum.shinnytech.com/wp-content/uploads/anspress-uploads/ff91ddc780adab162e593831819e04b4864d1923_4203.png" /></p>
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				<title>nabatieqiao 回答了 一个问题</title>
				<link>https://www.shinnytech.com/?p=19958</link>
				<pubDate>Fri, 26 Nov 2021 09:01:58 +0800</pubDate>

									<content:encoded><![CDATA[<p>while True:<br />
    api.wait_update()<br />
    print(datetime.time(datetime.now()).strftime(&#8220;%H:%M:%S&#8221;), &#8220;**&#8221; )<br />
    if api.is_changing(k.iloc[-1], &#8220;datetime&#8221;):  # [&hellip;]</p>
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				<title>nabatieqiao 回答了 一个问题</title>
				<link>https://www.shinnytech.com/?p=18888</link>
				<pubDate>Sat, 09 Oct 2021 01:38:02 +0800</pubDate>

									<content:encoded><![CDATA[<p>time.sleep(0.2)</p>
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				<title>nabatieqiao 回答了 一个问题</title>
				<link>https://www.shinnytech.com/?p=18883</link>
				<pubDate>Fri, 08 Oct 2021 14:22:29 +0800</pubDate>

									<content:encoded><![CDATA[<p>while循环不间断持续运行</p>
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				<title>nabatieqiao 提了一个新问题 问题</title>
				<link>https://www.shinnytech.com/?p=18882</link>
				<pubDate>Fri, 08 Oct 2021 14:17:52 +0800</pubDate>

									<content:encoded><![CDATA[<p> <img loading="lazy" src="https://www.shinnytech.com/wp-content/uploads/anspress-uploads/8ce76d617538f5a7471dd7f72dfb8eb43b345d72_4203.png" /></p>
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				<title>nabatieqiao 回答了 一个问题</title>
				<link>https://www.shinnytech.com/?p=17098</link>
				<pubDate>Fri, 03 Sep 2021 08:38:41 +0800</pubDate>

									<content:encoded><![CDATA[<p>我也遇到了订阅不同周期Kline会有延时或者不更新的问题，尤其是长周期kline。</p>
<p>可以订阅一个短周期kline，长周期用短周期在本地合成。</p>
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				<title>nabatieqiao 提了一个新问题 问题</title>
				<link>https://www.shinnytech.com/?p=15743</link>
				<pubDate>Sun, 23 May 2021 09:02:05 +0800</pubDate>

									<content:encoded><![CDATA[<p>def KD(df, n, m1, m2):<br />
new_df = pd.DataFrame()<br />
hv = df[&#8220;high&#8221;].rolling(n).max()<br />
lv = df[&#8220;low&#8221;].rolling(n).min()<br />
rsv = pd.Series(np.where(hv == lv, 0, (df[&#8220;close&#8221;] &#8211; lv) / (hv &#8211; lv) * 100))<br />
# new_df[&#8220;k&#8221;] = [&hellip;]</p>
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